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A canoe is designed to have very little drag when it moves along its length. Riley, mass 62 kg, sits in a 21 kg canoe in the middle of a lake. She dives into the water off the front of the canoe, along the axis of the canoe. She dives forward at 1.7 m/s relative to the boat.
1) Just after her leap, how fast is she moving relative to the water?
2) Just after her leap, how fast is the canoe moving relative to the water?

Respuesta :

onyebuchinnaji

(1) Riley velocity relative to the water after she jumps is 1.7 m/s.

(2) The velocity of the canoe relative to the water is 5.02 m/s.

The given parameters;

  • mass of Riley, m₁ = 62 kg
  • mass of canoe, m₂ = 21 kg
  • velocity of the Riley after jumping, v₁ = 1.7 m/s

(1) Since the lake is still, her velocity relative to the water after she jumps is 1.7 m/s.

(2) Apply the principle of conservation of linear momentum;

m₁v₁  =  m₂v₂

62 x 1.7 = 21v₂

105.4 = 21v₂

[tex]v_2 = \frac{105.4}{21} \\\\v_2 = 5.02 \ m/s[/tex]

Thus, after her leap, the velocity of the canoe relative to the water is 5.02 m/s.

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