Respuesta :

4x^2 y^3 × 2xy^4 =

4 × 2 × x^2 × x^1 × y^3 × y^4 =

8 × x^(2 + 1) × y^(3 + 4) =

8 × x^3 × y^7 =

8x^3 y^7

ANS

step 1- Equation at the end of step

step 2- Equation at the end of step

step 3- simplify

[tex] \\ \frac{ {2}^{2} {x}^{2} {y}^{3} }{ {2xy}^{4} } [/tex]

step 4- Dividing exponential expressions

[tex]\: {x}^{2} divided \: by \: {x}^{1} = {x}^{(2 - 1)} = {x}^{1} = x[/tex]

step 5- Dividing exponential expressions

[tex]\: \: {y}^{3} divided \: by \: {y}^{4} = {y}^{(3 - 4)} = {y}^{ - 1} = \frac{1}{ {y}^{1} } = \frac{1}{y} [/tex]

step 6- Dividing exponents

[tex] \: {2}^{2} divided \: by \: {2}^{1} = {2}^{(2 - 1)} = {2}^{1} = 2[/tex]

Final result

[tex] \\ \frac{2x}{y} [/tex]

Thank You !!!