What is the value of x in the equation
4z +16
12
= х - 4?

[tex] \frac{4x + 16}{12} = x - 4 \\ = > 4x + 16 = 12(x - 4) \\ = > 4x + 16 = 12x - 48 \\ = > 16 + 48 = 12x - 4x \\ = > 64 = 8x \\ = > x = \frac{64}{8} \\ = > x = 8[/tex]
x = 8