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3. The ratio of milk water in 55 liters of Adultered milk is 7:4. How much water must be added to make the mixture Ratio of 7:6? a)5 liters b)10 liters c)15 liters

3 The ratio of milk water in 55 liters of Adultered milk is 74 How much water must be added to make the mixture Ratio of 76 a5 liters b10 liters c15 liters class=

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towl35

Answer:

The answer is B 10 L

Step-by-step explanation:

let milk and water in the mixture be 7x and 4x equal 55L

[tex]7x + 4x = 55 \\ 11x = 55 \\ x = 5[/tex]

[tex]7(5) = 35l \: milk \\ 4(5) = 20l \: water[/tex]

let x Liters of water he added so that the ratio is 7:6

[tex] \frac{35l \: milk}{20l \: water + x} = \frac{7}{6} [/tex]

cross multiply

[tex]35l \: milk \times 6 = (20l \: water + x)7 \\ 210l \: m= 140l \: w + 7x \\ 210l \: m - 140l \: w = 7x \\ 70l = 7x \\ \frac{70}{7} = \frac{7x}{7 } \\ x = 10 l \: water[/tex]

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