Answer:
The acceleration of the car was one meter per second squared.
Explanation:
We can use one of the kinematic equations:
[tex]\displaystyle v_f = v_i + at[/tex]
Where v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time (in seconds).
The final velocity is 40 m/s, the initial velocity is 35 m/s, and the time is 5 s. Substitute and solve for a:
[tex]\displaystyle \begin{aligned}(40 \text{ m/s}) &= (35 \text{ m/s}) + a(5\text{ s}) \\ \\ 5 \text{ m/s} &= a(5\text{ s}) \\ \\ a &= 1\text{ m/s$^2$} \end{aligned}[/tex]
In conclusion, the acceleration of the car was one meter per second squared.
