Answer:
Y=3x+3
Step-by-step explanation:
Gradient = :[tex]\frac{y2-y1}{x2-x1}[/tex] = :[tex]\frac{3-15}{0-4}[/tex] = :[tex]\frac{-12}{-4}[/tex] = 3
Y= mx + c
y = 3x + c
Insert x and y values for first point(4,15)
15 = 3 (4) + c
15 = 12 + c
3 = c
Y=3x +3
Answer:
The equation of the line is y=3x+3
Step-by-step explanation:
y=mx+b is the y intercept form of the equation of this line.
m=slope, and we find the slope by the equation m=y2-y1/x2-x1. Plugging our number into that formula, we get m=3 - 15/ 0 - 4, or -12/-4, which simplifies to 3.
Now we can add our slope into the formula.
y=3x+b
Next, we solve for the y intercept, or b. You can use whatever point to get the answer, but I will use 4 ,15).
y=mx+b is the equation, or substituting the numbers, gets you 15=3×4+b. now solve for b: b=15-(3)(4). b=3.
now, with slope and y intercept plugged in, the final equation is. y=3x+3
