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An advertisement shows a 1239 kg car slowly pulling at constant speed a large passenger airplane to demonstrate the power of
its newly designed 85.7 hp (horsepower) engine. During the pull, the car passes two landmarks spaced 26.0 m apart in 14.3 s.
The passenger plane being towed is a Boeing 707 with a total weight of 62.5 tons.
Calculate the force that opposes the motion. Assume that the efficiency of the car is such that 15.4% of the engine power is
available to propel the car forward.
How much work is performed by the car on the airplane during this time? How much work is performed by the airplane on the car during this time?

Respuesta :

Answer:

Power = Work / Time

available power = .154 * 85.7 = 13.2 hp

1 hp = 746 watts (joule/sec)

13.2 hp = 13.2 * 746 = 9850 J/sec

Work = P * t = 9850 J/sec * 14.3 s = 141,000 joules

This is the work performed on the airplane and the car

Work = F * s   (force * distance)

F = 141000 J / 26 m = 5420 Newtons    opposes the motion

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