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f(x) = 732
g(x) = 3x + 2
Find
(1) (a). Include any restrictions on the domain.
, 3 > 0
OA () (x) = 0 + 0
B. (4) (z) = 2, 3
c. (4) (x) = x +
OD. () () + -1

fx 732 gx 3x 2 Find 1 a Include any restrictions on the domain 3 gt 0 OA x 0 0 B 4 z 2 3 c 4 x x OD 1 class=

Respuesta :

mhanifa

Answer:

  • Option D

Step-by-step explanation:

Given:

  • [tex]f(x) = \sqrt[3]{3x}[/tex]
  • [tex]g(x)=3x+2[/tex]

Find (f/g)(x):

  • [tex](f/g)(x)=f(x)/g(x)=\sqrt[3]{3x}/(3x+2)[/tex]

The restriction is, the denominator can't be zero:

  • 3x + 2 ≠ 0 ⇒ 3x ≠ -2 ⇒ x ≠ -2/3

Correct choice is D

Bora77

Step-by-step explanation:

d is the answer

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