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A car moving at 8.5 m/s crashes into a tree and stops in 0.32 s. Calculate the magnitude of the force, in newtons, the seatbelts exerts on a passenger in the car to bring him to a halt. The mass of the passenger is 66.5kg.

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Answer:

Explanation:

I=Q2- Q1

And I = F. (t2-t1)

t = 0,32s

v = 8,5 m/s

Q = m.v

Q=66,5.8,5 = 565,25 kg.m/s

F. (t2-t1) = 565,25

F.0,32 = 565,25

F = 1766,4 N

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