someone pls help meeeee!!!!!!

Step-by-step explanation:
y = y
x - 2 = 2x - 3 - 3x²
3x² + x - 2x = - 3 + 2
3x² - x = - 1
.
a = 3, b = -1, c = 0
.
[tex]\sf{x = \frac{-b \pm \sqrt{b^{2} - 4ac} }{2a} }[/tex]
[tex]\sf{x = \frac{- (-1) \pm \sqrt{-1^{2} - 4 (0)} }{2(3)} }[/tex]
[tex]\sf{x = \frac{ 1 \pm \sqrt{1 - 0} }{6} }[/tex]
[tex]\sf{x = \frac{ 1 \pm \sqrt{1} }{6} }[/tex]
[tex]\sf{x = \frac{ 1 + 1 }{6} }[/tex]
[tex]\sf{x = \frac{ 2 }{6} }[/tex]
[tex]\sf{x = \frac{ 1 }{3} }[/tex]
.
Substitution :
y = x - 2
y = ⅓ - 2
y = ⅓ - 6/3
y = - 5/3
y = - 1 ⅔
.