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Answer

[tex] | \sqrt \frac{3v}{\pi \: h} | = r[/tex]

The given formula for the volume of cone can be written as [tex]\sqrt{\frac{2V}{\pi h} }[/tex] in terms of V and h for r.

What is transposing a term in an expression or transpose method?

To bring a term from one side of an equation to the other, with corresponding change in sign or by doing opposite operations is called transposing a term in an expression.

According to the given question.

We have a formula for the volume of cone

[tex]V = \frac{1}{2} \pi r^{2} h[/tex]

To solve the the above formula for r we use transpose method.

Therefore,

[tex]V = \frac{1}{2} \pi r^{2} h[/tex]

⇒ [tex]2V = \pi r^{2}h[/tex]           (multiplying by 2 both the sides)

⇒ [tex]\frac{2V}{\pi h} =r^{2}[/tex]                (dividing both the sides by πh)

⇒ [tex]r=\sqrt{\frac{2V}{\pi h} }[/tex]

Hence, the given formula for the volume of cone can be written as [tex]\sqrt{\frac{2V}{\pi h} }[/tex] in terms of V and h for r.

Find out more information about transpose method here:

https://brainly.com/question/2263930

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