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A battery moves 150c of charge through a potential difference of 12v in 1 minute. Calculate the power developed in the battery.

Respuesta :

Answer:

V = W = 12 J/C * 150 C = 1800 J      work in moving 150 C of charge

P = W / t = 1800 J / 60 s  = 30 watts

Answer:

30 Watts

Explanation:

We're provided with the following information:

  • Amount of Charge flown (Q) = 150 C
  • Potential Difference (V) = 12 V
  • Time (T) = 1 min

= 60 seconds

Current:

Current is the rate of flow of charge ,i. e., The amount of charge flowing "per second":

[tex]\boxed{\mathfrak{Current(I)=\frac{Charge(Q)}{Time(T)} }}[/tex]

We have:

  • Charge flown (Q) = 150 C
  • Time (T) = 60 seconds

Finding the current flown using the above mentioned formula:

[tex]\implies \mathsf{I=\frac{150}{60} }[/tex]

[tex]\implies \mathsf{I=\frac{5}{2} }[/tex]

=> I = 2.5 A

A(Amperes) is the SI unit of Current

Relation between Power, Voltage and Current:

We've a relation between Power, Current and Voltage, derived with the help of  "Joule's Law of Heating", and that is:

[tex]\boxed{\mathfrak{Power(P)=Voltage(V) \times Current(I)}}[/tex]

We can finally find Power, Since we have:

  • Current (I) = 2.5 A
  • Voltage (V) = 12 V

=> P = 12 × 2.5

=> P = 30 W

W, Watts, is the Si unit of Power