[tex]growth\:=(\frac{present \: value}{past \: value})^{ \frac{1}{n} } \: - 1 [/tex]
past value = 1700 people
n = 2005 - 1983 = 22
growth rate = 190%
present value = ?
then,
[tex]190\% = ( \frac{?}{1700})^{ \frac{1}{22} } - 1[/tex]
1.9 = (x/1700) ^(1/22) - 1
1.9 + 1 = (x/1700) ^(1/22)
2.9 = (x/1700) ^(1/22)
log 2.9 = 1/22(logx - log 1700)
log2.9 = 1/22logx - 1/22log1700
log2.9 + 1/22log1700 = 1/22logx
log(2.9 * 1/22(1700)) = 1/22logx
log 224 = 1/22logx
log(224 - 1/22(x)) = 1
log(224 - 1/22(x)) = log 10
224 - 1/22(x) = 10
(234) * 22 = x
x = 5148.
Number of people to die from AIDS would have been 5148 if left unchecked.
That's what I found. Please feel free to tell me where am wrong.
All the best!
