Hint :-
- To find out the equation of the line we can use the point slope form of the line which is [tex] y - y_1 = m(x-x_1) [/tex]
Solution :-
The given point to us is , [tex](0,3)[/tex] and the slope of the line is 4 . On using the point slope form , we have ,
[tex]\implies y - y_1= m(x-x_1) \\\\\implies y-3 = 4(x-0) \\\\\implies y -3 = 4x \\\\\implies \boxed{ 4x - y + 3 =0}[/tex]
Hence the equation is 4x - y + 3 = 0
( for graph , see attachment ) .
