Answer:
[tex]x\leq 8\\[/tex]
Step-by-step explanation:
[tex]15(\frac{5x-1}{3} -\frac{1-2x}{5} )\leq( 8+x)15\\5(5x-1)-3(1-2x)\leq 120+15x\\25x-5-3+6x\leq 120+15x\\31x-8\leq 120+15x\\\\31x-15x\leq 120+8\\16x\leq 128\\x\leq 8[/tex]
