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A forklift pushes a box with a force of 500 N across the floor for a distance of 5.0 m, then turns around and pushes with the same force 5.0 m back to its original position. How much work did the forklift do during this time?

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chloeroebuck2021

Answer:

5,000J

Explanation:

Work = Force x Distance

Distance back and forth is canceled out, so either the answer is + or -

5.0m + 5.0m = 10.0m

500N x 10.0m = 5,000J

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