Respuesta :

discipulus

Answer:

[tex] \sum_{n = 0}^{6} 4 + 6n \\ n = 0 \rightarrow4\\ n = 1 \rightarrow10 \\ n = 2 \rightarrow16 \\ n = 3 \rightarrow22 \\ n = 4 \rightarrow28 \\ n = 5 \rightarrow34 \\ n = 6 \rightarrow40[/tex]

maniknandini

Answer:

∑-2 + 6n

Step-by-step explanation:

4, 10, 16, ......

7 terms

nth term is a + (n - 1)*d

= 4 + (n -1 )*6

= 4 + 6n - 6

= -2 + 6n

so sigma notation would be

∑-2 + 6n

u can also check terms

n = 1  -> -2 + 6 = 4

n = 2 -> -2 + 6*2 = 10

n = 3 -> -2 + 6*3 = 16

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