arelihernandez0210
contestada

A physics student stands at the top of a set of bleachers. They drop a basketball and it lands 2.4 seconds later.

d.) How high are the bleachers ?
e.) How fast was the basketball traveling at the time it landed ?​

Respuesta :

KevinPug

Answer:

x=48.12 m

Vf=23.544 m/s

Explanation:

a=g

t=2.4

Vf=?

Vø=0

Vf=Vø+at

Vf=0+(9.81)(2.4)=23.544

x=Xø+Vøt+1/2at^2

x=1/2at^2

x=(1/2)(9.81)^2=48.11805

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