Respuesta :
Using sequences concepts, it is found that:
A. As the quotient between consecutive terms is the same, the data is a geometric sequence.
B. The recursive formula is:
[tex]f(n) = f(n-1)2^{n-1}, f(1) = 2[/tex]
C. She will need a time of 1024 units to complete the 10th station.
- In a sequence, if the difference between consecutive terms is the same, the sequence is arithmetic.
- If the quotient between consecutive terms is the same, the sequence is geometric.
Item a:
When x increases by 1, y is multiplied by 2, hence, as the quotient between consecutive terms is the same, the data is a geometric sequence.
Item b:
The recursive formula for a geometric sequence with common ratio [tex]q[/tex] and first term [tex]a_1[/tex] is given by:
[tex]f(n) = f(n-1)q^{n-1}, f(1) = a_1[/tex]
Hence, since [tex]a_1 = 2, q = 1[/tex]
[tex]f(n) = f(n-1)2^{n-1}, f(1) = 2[/tex]
Item c:
The explicit formula for a geometric sequence with common ratio [tex]q[/tex] and first term [tex]a_1[/tex] is given by:
[tex]a_n = a_1q^{n-1}[/tex]
Hence, in this question:
[tex]a_n = 2(2)^{n-1} = 2^{1 + n - 1} = 2^n[/tex]
For the 10th station:
[tex]a_n = 2^10 = 1024[/tex]
She will need a time of 1024 units to complete the 10th station.
A similar problem is given at https://brainly.com/question/25403784