Answer:
See below:
Step-by-step explanation:
So we know that an apple and 3 bannans are dollar 2.50
We also know that 2 apples and 5 bannanas are dollar 4.50.
Therefore, if we subtract 2 apples and 5 bannanas from 1 apple and 3 bannanas we will get a price.
Therefore, 1 apple and 2 bannanas are 2 dollars. (4.50 - 2.50 = 2)
Now, we can multiply by 3 to get it for 3 apples and 6 bannanas.
3*1 + 3*2 = 2*3
3a + 6b = 6 dollars.
The cost of 3 apples and 6 bananas is $7 and this can be determined by forming the linear equation in two variables.
Given :
Let the cost of one apple be 'x' and the cost of one banana be 'y'. Then the cost of an apple and 3 bananas is given by the equation:
x + 3y = 2.5 --- (1)
The cost of 2 apples and 5 bananas is given by the equation:
2x + 5y = 4.5 ---- (2)
Now, solve the equation (1) for 'x'.
x = 2.5 - 3y --- (3)
Now, put the value of 'x' in equation (2).
2(2.5 - 3y) + 3y = 4.5
5 - 6y + 3y = 4.5
0.5 = 3y
[tex]y = \dfrac{1}{6}[/tex]
Now, put the value of 'y' in the equation (3).
[tex]\rm x = 2.5-3\times \dfrac{1}{6}[/tex]
x = 2
Now, the cost of 3 apples and 6 bananas will be:
[tex]3 \times 2 + 6 \times \dfrac{1}{6} = 7[/tex]
So, the cost of 3 apples and 6 bananas is $7.
For more information, refer to the link given below:
https://brainly.com/question/13911928
