Answer:
We know that,
[tex]a^{x} *a^{y} =a^{x+y}[/tex]
[tex]a^{-x} =\frac{1}{a^{x} }[/tex]
[tex]\frac{1}{a^{-x} } =a^{x}[/tex]
Let's solve now
[tex]\frac{3^{4} *5^{2} }{5^{8}*5*3^{-1} }[/tex]
[tex]\frac{3^{4}*3^{1} }{5^{-2} *5^{8} *5}[/tex]
[tex]\frac{3^{4+1} }{5^{-2+8+1} }[/tex]
[tex]\frac{3^{5} }{5^{7} }[/tex]
Therefore,
[tex]\frac{3^{5} }{5^{7} } = \frac{3^{w} }{c^{x} }[/tex]
So,
w = 5
c = 5
x = 7
Hope this helps you.
Let me know if you have any other questions :-)
