please help for my math i rlly need it ill give big points and brainliest

Answer:
a) x2 = 10
b) x2 − 40 = 0
c) 3x2 − 600 = 0
d) x2 + 12 = 0
Answer:
[tex]\frac{6(2a-4c)-6(6a-4b)+3(4b-8c)}{4} \\[/tex]
[tex]\frac{12a-24c-36a+24b+12b-24c}{4}[/tex]
[tex]\frac{12a-36a+24b+12b-24c-24c}{4}[/tex]
[tex]\frac{-24a+36b-48c}{4}[/tex]
[tex]-6a+9b-12c[/tex]
[tex]-3(2a-3b+4c)[/tex]
So,
[tex]-3(2a-3b+4c)=X(2a+Yb+Zc)[/tex]
X = (-3)
Y = (-3)
Z = 4
Hope this helps you.
Let me know if you have any other questions :-)