Respuesta :

Answer:

a) x2 = 10

b) x2 − 40 = 0

c) 3x2 − 600 = 0

d) x2 + 12 = 0

Hi1315

Answer:

[tex]\frac{6(2a-4c)-6(6a-4b)+3(4b-8c)}{4} \\[/tex]

[tex]\frac{12a-24c-36a+24b+12b-24c}{4}[/tex]

[tex]\frac{12a-36a+24b+12b-24c-24c}{4}[/tex]

[tex]\frac{-24a+36b-48c}{4}[/tex]

[tex]-6a+9b-12c[/tex]

[tex]-3(2a-3b+4c)[/tex]

So,

[tex]-3(2a-3b+4c)=X(2a+Yb+Zc)[/tex]

X = (-3)

Y = (-3)

Z = 4

Hope this helps you.

Let me know if you have any other questions :-)