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The diagram shows the position of the principal lines in the visible spectrum of atomic hydrogen
and some of the corresponding energy levels of the hydrogen atom. Determine the energy of a photon of blue light (435nm) emitted in the hydrogen spectrum

Please help The diagram shows the position of the principal lines in the visible spectrum of atomic hydrogen and some of the corresponding energy levels of the class=

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The energy of the photon of blue light is  4.55 × 10^-19 J. Blue light is in the visible spectrum.

Using the formula;

E = hc/λ

E = energy of the photon = ?

h = Plank's constant = 6.6 × 10^-34 Js

c = Speed of light = 3 × 10^8 m/s

λ = wavelength of light = 435nm or 435  × 10^-9 m

Substituting values;

E =  6.6 × 10^-34 Js ×  3 × 10^8 m/s/435  × 10^-9 m

E = 4.55 × 10^-19 J

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