Answer:
We know that,
[tex]a^{x} *a^{y} =a^{x+y}[/tex]
[tex](a^{x} )=a^{xy}[/tex]
[tex]a^{-x}=\frac{1}{a^{x} }[/tex]
[tex]\frac{1}{a^{-x} } =a^{x}[/tex]
Let us solve now
[tex](5^{3} *2^{-6} )^{-2}[/tex]
[tex]5^{(3*-2)} *2^{(-6*-2)}[/tex]
[tex]5^{-6} *2^{12}[/tex]
[tex]\frac{2^{12} }{5^{6} }[/tex]
So,
[tex]\frac{2^{12} }{5^{6} } =\frac{2^{w} }{c^{x} }[/tex]
Therefore,
w = 12
c = 5
x = 6
Hope this helps you.
Let me know if you have any other questions :-)
