Find the value of x in the triangle shown below.
1
4
Choose 1 answer:

Answer:
x = [tex]\sqrt{17}[/tex]
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is
x² = 4² + 1² = 16 + 1 = 17 ( take square root of both sides )
x = [tex]\sqrt{17}[/tex]
Answer:
x = 4.12
Step-by-step explanation:
Remark
Use the Pythagarian Theorem a^ + b^2 = c^2
a = 1
b = 4
c = ?
Solution
1^2 + 4^2 = c^2 Expand
1 + 16 = c^2 Combine
c^2 = 17 Take the square root of both sides
sqrt(c^2) = sqrt(17)
c = 4.12 Answer