Respuesta :

Answer:

[tex] \sqrt{58} [/tex]

Answer:

B

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

x² = 3² + 7² = 9 + 49 = 58 ( take square root of both sides )

x = [tex]\sqrt{58}[/tex] → B