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Clare went to a concession stand that sells pretzels for $3.25, drinks for $1.85, and bags of popcorn for $0.99 each. She bought at least one of each item and spent no more than $10.

Could Clare have purchased 2 pretzels, 2 drinks, and 2 bags of popcorn? Explain your reasoning.

Respuesta :

No because if you add all of the things she had already bought it would have been 6.09 and if she had bought more the total would’ve been 12.18

$3.25+$1.85+$0.99= 6.09
$6.09- $10.00= $3.91

RevyBreeze

Answer: No Clare can't purchased 2 pretzels, 2 drinks, and 2 bags of popcorn

Step-by-step explanation:

Given:

Pretzel = 3.25

Drinks = 1.85

Popcorn = 0.99

No more than $10

To Find:

Could Clare have purchased 2 pretzels, 2 drinks, and 2 bags of popcorn?

Solution:

2 pretzels = 3.25x2

2 Drink = 1.85x2

2 Popcorn = 0.99x2

3.25x2 = 6.5

1.85x2= 3.7

0.99x2= 1.98

Then add all the answer up

6.5+3.7+1.98= 12.18

Therefore, Clare can't purchased 2 pretzels, 2 Drink, and 2 bags of popcorn.

She can buy 2 pretzels, 1 Drink, and 1 bag of popcorn and Cost 9.34 and still have 0.66

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