This question requires the application of the appropriate trigonometric function to solve it. So that the appropriate answer is; the shooter was on the second floor window = 14 feet from the grou i.e option B.
Let the height from the the ground to tip of the gun be represented by y. Then applying the appropriate trigonometric function, we have:
Tan θ = [tex]\frac{opposite}{adjacent}[/tex]
So that;
Tan 11 = [tex]\frac{y}{78}[/tex]
⇒ y = Tan 11 x 78
= 0.1943 x 78
y = 15.1554
y = 15 feet
Therefore, considering some other factors as regards the woman's ankle to the ground and the gun's tip in relation to the floor of the second floor, then we can say that the shooter was on the second floor window = 14 feet from the ground.
The required answer is option B.
A sketch for the question is attached to this answer for more understanding.
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