contestada

Daniel has 23 coins in nickels and dimes
in his pocket, for a total of $2.20. How
many of each coin does he have?
First, create the equations below, where N
stands for nickels and D stands for dimes.
Don't forget to pick out your puzzle pieces.
0.05N +[? ]D = 2.20; N + D =
Remember: A nickel is worth $0.05 and a
dime is worth $0.10.

Respuesta :

Using a system of equations, it is found that Daniel has 2 nickels and 21 dimes.

For the system, we have that:

  • N is the number of nickels.
  • D is the number of dimes.

He has 23 coins, hence:

[tex]N + D = 23 \rightarrow D = 23 - N[/tex]

He has a total of $2.20, hence, considering the value of each coin:

[tex]0.05N + 0.1D = 2.20[/tex]

From the first equation, [tex]D = 23 - N[/tex], hence, replacing in the second:

[tex]0.05N + 0.1D = 2.20[/tex]

[tex]0.05N + 0.1(23 - N) = 2.20[/tex]

[tex]-0.05N = -0.1[/tex]

[tex]0.05N = 0.1[/tex]

[tex]N = \frac{0.1}{0.05}[/tex]

[tex]N = 2[/tex]

Then:

[tex]D = 23 - N = 23 - 2 = 21[/tex]

Daniel has 2 nickels and 21 dimes.

To learn more about system of equations, you can take a look at https://brainly.com/question/14183076

Otras preguntas