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Lupert walked 5.8 m east in 8.9 s, stopped for 3.7 s, turned North and went 7.9 m in 12.5 s, stopped for 6.3s , and then went 3.2 m west in 4.7s. What was his average speed?

Respuesta :

The average speed of Lupert for the entire journey is 4.58 m/s.

The given parameters;

  • initial position of Lupert, = 5.8 m east
  • time of motion, = 8.9 s, extra time = 3.7 s
  • second position of Lupert, = 7.9 m, North
  • time of motion, = 12.5 s, extra time = 6.3 s
  • final position of Lupert = 3.2 m west
  • time of motion = 4.7 s

The average speed of Lupert is calculated as the ratio of the total distance to total time of motion;

[tex]average \ speed = \frac{(5.8 \times 8.9) \ + \ (7.9 \times 12.5) \ + \ (3.2 \times 4.7)}{8.9 \ + \ 3.7 \ + \ 12.5 \ + \ 6.3\ +\ 4.7} \\\\average \ speed = \frac{165.41}{36.1} \\\\average \ speed =4.58 \ m/s[/tex]

Thus, the average speed of Lupert for the entire journey is 4.58 m/s.

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