This question involves the concepts of torque, applied force, and force arm.
The net torque about the axle will be "0.94 N.m clockwise".
The net torque can simply be found by adding the torques produced by every force about the axle, that is at some perpendicular distance from the axle and whose line of action does not touch with the center point. We will take the clockwise direction as negative here, and the counter-clockwise direction as positive. The torque due to a force can simply be given as the product of the force and the perpendicular distance between center point and force, also known as force arm.
[tex]Net\ Torque = T = -(30\ N)(0.1\ m)+(20\ N)(0.05\ m)+(30\ N)(Sin\ 45^o)(0.05\ m)[/tex]
T = -3 N.m + 1 N.m + 1.06 N.m
T = -0.94 N.m (negative sign shows clockwise direction)
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