thunderbolt07
contestada

Which of the following equations have no solution? Check all that apply.
A. 6x + 1 = 3(2x - 4)
B. 02-5x = 7x - 12
C. 04(3 - x) = 2(6 - 2x)
D. 05(x + 2) = 2(x – 4)
E. 4(x + 3) = 4(x - 1)
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Respuesta :

Lakesman

Answer:

C

Step-by-step explanation:

4(3 - x) =2(6 - 2x)

(4x3) + (4x(-x))=(2x6) + (2x(-2x))

12 + (-4x) = 12 + (-4x)

12 - 4x = 12 - 4x

collect like terms

12 - 12 = -4x + 4x

0 = 0

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