Answer:
x = (-3+√15)/2 or, x = (-3-√15)/2
Step-by-step explanation:
2x²+6x-3=0
Standard quadratic formula,
ax²+bx+c = 0
where,
x =(-b±[tex]\sqrt{b^{2}-4ac }[/tex])/2a ...............................(i)
Here,
a = 2
b = 6
c = -3
Putting the values in equation(i), we get,
x = (-6±[tex]\sqrt{6^{2} -4.2.(-3)}[/tex])/2.2
=(-6 ± √60)/4
=(-6 ± 2√15)/4
= (-3 ± √15)/2
Therefore, x = (-3+√15)/2 or x = (-3-√15)/2 :)