The potential difference at the point is 44 V
From the question given above, the following data were obtained:
Energy (E) = 44 J
Charge (Q) = 2 C
Potential difference (V) =?
The potential difference can be obtained as follow:
E = ½QV
44 = ½ × 2 × V
44 = 1 × V
V = 44 V
Therefore, the potential difference is 44 V
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