Respuesta :
- Let Rebecca drove=x
- Jared drove=3x
ATQ
[tex]\\ \sf\longmapsto x+3x=240[/tex]
[tex]\\ \sf\longmapsto 4x=240[/tex]
[tex]\\ \sf\longmapsto x=60[/tex]
- Rebecca=60mi
- Jared=240-60=180mi
Let the value of Rebecca drove be a
Given Jared drove = 3a
Let's form a equation –
[tex] \sf \longmapsto \: 3a + a = 240[/tex]
There we have a equation!
Let's start solving.
[tex] \sf \longmapsto \: 3a + 1a = 240[/tex]
[tex] \sf \longmapsto \: 4a= 240[/tex]
[tex]\sf \longmapsto \: a = 240/4[/tex]
[tex]\sf \longmapsto \: a = 60(Rebecca \:drove)[/tex]
- Solving Further
Let's now find the no. of miles Jared drove.
[tex]\sf \longmapsto \: 240 - 60[/tex]
[tex]\sf \longmapsto \: 180( Jared\: drove)[/tex]
So Jared drove –
- 180 miles
Rebecca drove–
- 60 miles