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F varies jointly as q1 and q2 and inversely as the square of d.

If F=8 when q1=2, q2=8, and d=4, find F when q1=28, q2=12, and d=2

Respuesta :

Answer:

F =672

Step-by-step explanation:

joint variation is of the form

F = k *q1 * q2

Inversly means divide

F = k * q1 * q2

     -------------------

              d^2

We know  F=8 when q1=2, q2=8, and d=4  so we can solve for k

8 = k * 2*8

    -----------------

          4^2

8 = 16k

     ----

     16

8 = k

Substituting

F = 8 * q1 * q2

     -------------------

              d^2

Let q1=28, q2=12, and d=2

F = 8 * 28 * 12

   ----------------

    2^2

F = 2688

      -------

         4

F =672

We are given:

F varies jointly (directly) with q1 and q2, which means that F is proportional to both q1 and q2. also,

F varies inversely with d², so F is inversely proportional to the square to d

Finding a mathemetical experssion:

using the above information, we can say that:

F ∝ q₁

F ∝ q₂

F ∝ 1/(d²)

joining these together, we get:

F ∝ q₁q₂ / d²

let's say that 'k' is the constant of proportionality in this case,

F = k (q₁q₂ / d²)

First case:

F = 8, q₁ = 2, q₂ = 8, d = 4

we can use these values in our expression to find k

[tex]8 = k\frac{2*8}{4^2}[/tex]

[tex]8 = k\frac{16}{16}[/tex]

k = 8

Finding F in the second case:

q₁ = 28, q₂ = 12, d = 2, k = 8

[tex]F = k\frac{q_{1}*q_{2}}{d^2}[/tex]

[tex]F = 8(\frac{28*12}{2^2})[/tex]

[tex]F = 8(\frac{336}{4})[/tex]

[tex]F = 2(336)[/tex]

F = 672 N