Step-by-step explanation:
For first picture,
Here Given,
x = White rectangular box
-x = Black rectangular box
1 = White square
-1 = Black square
Condition,
No. of White rectangular boxes = 5
- (On putting the value x) = 5x
No. of Black rectangular boxes = 8
- (On putting the value -x) = -8x
No. of White square boxes = 9
- (On putting the value 1) = 9
No. of Black square boxes = 4
- (On putting the value -1) = -4
Therefore Simplification,
5x + (-8x) + 9 + (-4)
= - 3x + 5 (Ans) (option D)
For second picture,
Here Given,
x = White rectangular box
-x = Black rectangular box
1 = White square
-1 = Black square
Condition,
Left side,
No. of White rectangular boxes = 7
- (On putting the value x) = 7x
No. of Black rectangular boxes = 3
- (On putting the value -x) = -3x
No. of White square boxes = 1
- (On putting the value 1) = 1
No. of Black square boxes = 2
- (On putting the value -1) = -2
Right side,
No. of White rectangular boxes = 1
- (On putting the value x) = x
No. of Black rectangular boxes = 3
- (On putting the value -x) = -3x
No. of White square boxes = 8
- (On putting the value 1) = 8
No. of Black square boxes = 3
- (On putting the value -1) = -3
Therefore Equation,
7x - 3x + 1 - 2 = x - 3x + 8 - 3
=> 6x = 6
=> x = 1 (Ans) (option B)
For third picture,
Given values,
a = 13, b = 3, c = 6
Solution,
[tex](26 - a) + \frac{ - 2bc}{2} + \sqrt{289} [/tex]
(On putting values of a, b and c)
[tex] = (26 - 13) + \frac{ - 2 \times 3 \times 6}{2} + \sqrt{289} [/tex]
= 13 + (-18) + 17
= 12 (Ans) (option A)
For fourth picture,
Given values,
x = 14, y = 5, z = 6
Solution,
[tex] (25 - x) + \frac{4yz}{2} [/tex]
(On putting values of x, y and z)
[tex] = (25 - 14) + \frac{4 \times 5 \times 6}{2} [/tex]
= 11 + 60
= 71 (Ans)
