A water sprinkler has a rotational motion in order to reach a broad area
from its stationary location.
The time it takes the sprinkler to reach the far right position is 36 seconds.
Reasons:
The given parameter are;
The angular speed of the water sprinkler, ω = 5° per second
Location where the sprinkler starts = The far left position
Required:
The time it takes the sprinkler to reach the far right position.
Solution;
The angle covered by moving from the far left to the far right, θ = 180°
Time required is given as follows;
[tex]\omega = \mathbf{\dfrac{\theta}{t}}[/tex]
Therefore;
[tex]t = \dfrac{\theta}{\omega}[/tex]
Which gives;
[tex]t = \dfrac{180 ^{\circ}}{5^{\circ}/s} = 36 \, s[/tex]
The time it takes the sprinkler to reach the far right position, t = 36 seconds.
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