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A gas mixture with a total pressure of 4.6 atm is used in a hospital. If the mixture contains 5.4 mol of nitrogen and 1.4 mol of oxygen, what is the partial pressure, in atmospheres, of each gas in the sample?

Respuesta :

Considering the Dalton's partial pressure, the partial pressure of nitrogen and oxygen is 3.634 atm and 0.966 atm  respectively.

The pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

[tex]P_{T} =P_{1} +P_{2} +...+P_{n}[/tex]

where n is the amount of gases.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture.

The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present:

[tex]x_{A} =\frac{n_{A} }{n_{total} }[/tex]

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

[tex]P_{A} =x_{A} P_{T}[/tex]

In this case, the mixture contains 5.4 mol of nitrogen and 1.4 mol of oxygen. So, the total number of moles of all the components present is 5.4 moles + 1.4 moles=  6.8 moles.

Then, the mole fraction of each gas can be calculated as:

  • [tex]x_{nitrogen} =\frac{n_{nitrogen} }{n_{total} }=\frac{5.4 moles}{6.8 moles} = 0.79[/tex]
  • [tex]x_{oxygen} =\frac{n_{oxygen} }{n_{total} }=\frac{1.4 moles}{6.8 moles} = 0.21[/tex]

So, being 4.6 atm the total pressure of the gas mixture, the partial pressure of each gas can be calculated as:

[tex]P_{nitrogen} =x_{nitrogen} P_{T}[/tex]= 0.79× 4.6 atm= 3.634 atm

[tex]P_{oxygen} =x_{oxygen} P_{T}[/tex]= 0.21× 4.6 atm= 0.966 atm

In summary, the partial pressure of nitrogen and oxygen is 3.634 atm and 0.966 atm  respectively.

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