A marble is rolled off of a 1.10 meter tall table and into a cup 2.4 meters away . How fast must the ball be rolling to land in the cup?

Respuesta :

Answer:

The ball must be rolling at around 5.12 m/s.

Explanation:

vertical

Δy = -1.1 m

vᵢᵧ = 0 m/s

a = -9.8 m/s²

Δy = vᵢᵧt + ½at²

-1.1 = 0t + ½(-9.8)t²

-1.1 = -4.9t²

t² = 0.22

t = 0.47 s

horizontal

Δx = vt

2.4 = 0.47v

v = 5.12 m/s

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