If 45.0 liters of oxygen is measured at 24.0C, what would be its volume at standard temperature?
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Respuesta :

The volume of the oxygen gas at standard temperature  is 41.36 liters.

The given parameters;

  • initial volume of oxygen, V₁ = 45 L
  • temperature of oxygen, T₁ = 24 ⁰C = 297 K
  • standard temperature, T₂ = 0 ⁰C = 273 K

The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1 T_2}{T_1} \\\\V_2 = \frac{45 \times 273}{297} \\\\V_2 = 41.36 \ L[/tex]

Thus, the volume of the oxygen gas at standard temperature  is 41.36 L.

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