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How many moles of NO₂ would be required to produce 5.73 moles of HNO₃ in the presence of excess water in the following chemical reaction?
3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

Respuesta :

Answer:

8.595 mol NO2

Explanation:

5.73 mol HNO3 * [tex](\frac{3 mol NO2}{2 mol HNO3})[/tex] = 8.595 mol NO2

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