The condition for ∆ABC to be similar to ∆EDF is that; ∠B = ∠D
Similar triangles
In the question, the ratio should be AB/DE = BC/FD = AC/ EF
We can also write the ratios of the corresponding sides as:
AB/ED = BC/DF = AC/FE
Therefore, ∆ABC is similar to ∆EDF
Thus, the corresponding angles would be, ∠B and ∠D.
And we know that corresponding angles are equal.
Thus, the condition for ∆ABC to be similar to ∆EDF is that;
∠B = ∠D
Read more on similar triangles at; https://brainly.com/question/14285697
