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HayabusaBrainly

>> Asnwer

________

[tex] \: [/tex]

[tex] \frac{2x + 8}{3} \geqslant 4[/tex]

[tex]2x + 8 \geqslant 4 \times 3[/tex]

[tex]2x + 8 \geqslant 12[/tex]

[tex]2x \geqslant 12 - 8[/tex]

[tex]2x \geqslant 4[/tex]

[tex]x \geqslant 2[/tex]

Hello there! :)

First, we have to get rid of the fraction by multiplying both sides by 3:

2x+8≥12

Now, we move all the numbers (constants) to the right:

2x≥12-8

2x≥4

Divide both sides by 2:

x≥2

Therefore, x≥2

Hope it helps you!

~Just a felicitous girlie

#HaveAGreatDay

[tex]SilentNature :)[/tex]

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