Answer:
[tex]t= \frac12C +3[/tex]
Step-by-step explanation:
Let's first write the data you have in an equation form:
[tex]C= -6 + 2t[/tex]. When t = 0, at dawn, you get -6°C so we're good. But you've ben asked the inverse relationship, so let's solve for t instead.
[tex]-6+2t = C\\2t = C+6\\t= \frac12(C+6)\\t= \frac12C +3[/tex]
Last two are both viable solution, only difference is in form. I do prefer the last option since it makes it easiest at a glance to answer to the question "at what time there's a temperature of 0°C?"
