When we add the two reactions X and Y as shown, we obtain the reaction Z; 2CH4(g) +3O2(g) + O2(g) → 4H2O(g) + 2CO2(g)
From the full question, we can see that reaction X is given as;
2CH4(g) +3O2(g) →2CO(g) + 4H2O(g)
Reaction Y is given as;
2CO(g) + O2(g) → 2CO2(g)
If we add the two reactions together, we have;
2CH4(g) +3O2(g) + 2CO(g) + O2(g) → 2CO(g) + 4H2O(g) + 2CO2(g)
We now have to cancel out 2CO(g) on both sides of the reaction equation;
2CH4(g) +3O2(g) + O2(g) → 4H2O(g) + 2CO2(g)
Hence the reaction Z is 2CH4(g) +3O2(g) + O2(g) → 4H2O(g) + 2CO2(g)
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