Answer:
718.6 gm
Explanation:
The reaction is: Fe2O3 (s) + 2Al (s) → 2Fe (l) + Al2O3 (s)
What mass, in grams, of iron (III) oxide reacted to produce 4.5 mol of Al2O3
1 mole of Fe2Os produces 1 mol of Al2O3
so 4.5 mols Fe2O3 would produce 4.5 mols Al2O3
the molecular mass of Fe2O3 is
(2 X 55.85) + (16 X 3) =
111.7 + 48 =
159.7
4.5 mols Fe2O6 weighs
4.5 X 159.7 =
718.6 gm
check:
718.6 gm of Fe3O2
