Factor the expression into an equivalent form.
12y^2-75

Answer:
3rd option
Step-by-step explanation:
You first notice that 12 and 75 are multiples of 3. Your expression becomes
[tex]3(4y^2-25)[/tex]. At this point you should recognize it's [tex](2y)^2[/tex] and [tex]5^2[/tex]. The second term gets factored as a difference of squares: [tex]3(2y+5)(2y-5)[/tex]