Respuesta :

Answer:

h'(x) = -10x + 20

Step-by-step explanation:

To get the derivative of [tex]ax^{n}[/tex], simply use the following formula:

[tex]a(n)x^{n-1}[/tex]

We have the function, h(x) = -5x^2 + 20x

Using the formula, we get the derivative to be:

-10x + 20

so h'(x) = -10x + 20