Answer:
1.31 X 10^ -10 joules per Fe 56 atom
Explanation:
The mass of a proton is 1.673 × 10-24 g. The mass of a neutron is 1.675 × 10-24 g. The mass of the nucleus of an 56Fe atom is 9.289 × 10-23 g. What is the nuclear binding energy (in J) for 56Fe? (c = 3.00 × 108 m/s)
some of the theoretical mass will be converted to binding energy
by Einstein's famous relativity equation
E = mc^2
where E is in joules, m is in Kgm. c is in m/sec
56Fe is element 26 so it has 26 protons and 56 -26 =30 neutrons
its theoretical nuclear mass is
(26 X 1.673 X 10^-24) + (30X1.675 X 10^-24) =
(43.498 X 10^-24) + (50.250 X 10^-24)=
93.748 X 10^24 gm
but its actual mass is 9.289 X 10^-23 g or
92.289 X 10^-24 g
the mas defect is the theoretical mass minus the actual
1.459 X 10^-24 gm =^
1.459 X 10^-27 Kgm
c = 3.00 X 10* m/s=
so joules of binding energy = (1.459 X 10^-27) X 9 X10^16)
1.31 X 10^ -10 joules per Fe 56 atom
